bsp; { if (X直连(x1, x, y1) == true && 地图[y1 * 尺寸 + x] == 已消除 && 一折连(x, y1, x2, y2) == true) { z1.X = x; z1.Y = y1; z2.X = x; z2.Y = y2; return true; } } if (X直连(x1, -1, y1)) { if (X直连(x2, -1, y2)) { z1.X = -1; z1.Y = y1; z2.X = -1; z2.Y = y2; return true; } } return false; } private bool 上边(int x1, int y1, int x2, int y2) { &n
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