C#如何让程序能够开机自动运行
这个是应该写注册表么？？
就30分了，还望不吝赐教啊！！
//此方法把启动项加载到注册表中 //获得应用程序路径 string strAssName = Application.StartupPath + @"\" + Application.ProductName + @".exe"; //获得应用程序名 string ShortFileName = Application.ProductName; RegistryKey rgkRun = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true); if (rgkRun == null) { rgkRun = Registry.LocalMachine.CreateSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run"); } rgkRun.SetValue(ShortFileName, strAssName); //此删除注册表中启动项 //获得应用程序名 string ShortFileName = Application.ProductName; RegistryKey rgkRun = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true); if (rgkRun == null) { rgkRun = Registry.LocalMachine.CreateSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run"); } rgkRun.DeleteValue(ShortFileName, false);
Public static bool Regexe(string filepath,string key) { if(file(filepath).Exist) { RegistryKey rgkRun = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true); if (rgkRun == null) { rgkRun = Registry.LocalMachine.CreateSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run"); rgkRun.SetValue(filepath, key); } }
把程序拖到启动里面应该简单点