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ψk = 1.1-0.65/) 混规(7.1.2－2)
= 1.1-0.65*2.01/(1.007%*209.400)
= 0.480
ψq = 1.1-0.65/) 混规(7.1.2－2)
= 1.1-0.65*2.01/(1.007%*176.989)
= 0.367
4) 计算钢筋弹性模量与混凝土模量的比值
αE = /
= 2.00*1/(3.00*1)
= 6.667
5) 计算受压翼缘面积与腹板有效面积的比值
矩形截面， = 0
6) 计算纵向受拉钢筋配筋率ρ
ρ = As/(b*)
= 604/(1000*95)
= 0.636%
7) 计算受弯构件的短期刚度
s = *As/[1.15*+0.2+6*αE*ρ/(1+ 3.5*)] 混规(7.2.3-1)
= 2.00*1*604*9/[1.15*0.480+0.2+6*6.667*0.636%/(1+3.5*0.0)]
= 10.831*1 kN*
s = *As/[1.15*+0.2+6*αE*ρ/(1+ 3.5*)] 混规(7.2.3-1)
= 2.00*1*604*9/[1.15*0.367+0.2+6*6.667*0.636%/(1+3.5*0.0)]
= 12.444*1 kN*
4.计算受弯构件的长期刚度B
1) 确定考虑荷载长期效应组合对挠度影响增大影响系数θ
当ρ`=0时，θ=2.0 混规(7.2.5)
2) 计算受弯构件的长期刚度 B
Bk = Mk/(Mq*(θ-1)+Mk)*s 混规(7.2.2-1)
= 10.456/(8.838*(2.0-1)+10.456)*10.831*1
= 5.870*1 kN*
Bq = s/θ 混规(7.2.2-2)
= 12.444/2.000*1
= 6.222*1 kN*
B = min(Bk,Bq)
= min(5.870,6.222
= 5.870*1 kN*
5.计算受弯构件挠度
max = 5*)/(384*Bk)
= 5*(7.81+3.500)*2.7/(384*5.870*1)
= 13.728 mm
6.验算挠度
挠度限值=/25=2.72/25=108.800 mm
ma=13.728mm≤=108.800mm，满足规范要求!
4.7 裂缝宽度验算:
1.计算准永久组合弯距值Mq:
Mq =+
= + )/8