nω − 12ω − E g√ng√n nω − 12ω − E = 0. (12)That is to say, (nω − 12ω − E)2= (g√n)2. So, we obtain E1 = nω − 12ω − g√n andE2 = nω − 12ω + g√n. Be taking the result back to eigenequation, and resulting from thefact that C1 and C2 satisfy the normalization condition, it can be written as[sinθ cosθ]T.Therefore, we have
Simulation of JC model in Linear Optics(2):http://www.youerw.com/yingyu/lunwen_50432.html
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