当 λy < 0.3 时,取 λy = 0.3
βy = 1.75 / (λy + 1.0) = 1.75/(0.300+1.0) = 1.346
βhs * βy * ft * bxo * ho = 1.00*1.346*1.43*2500*790 = 3809561N
≥ Vx = 2927070N,满足要求。
(2)、Y方向斜截面受剪承载力计算:
扣除承台及其上填土自重后 Y 方向斜截面的最大剪力设计值:
Vy = Max{N1 + N3, N2 + N4} = 2927070N
承台斜截面受剪承载力按下列公式计算:
Vy ≤ βhs * βx * ft * byo * ho (基础规范 8.5.18-1)
Y 方向上自桩内边缘到最近柱边的水平距离:
ax = 750 - hc / 2 - bp / 2 = 750-700/2-433/2 = 183mm
λx = ax / ho = 183/(900-110) = 0.232
当 λx < 0.3 时,取 λx = 0.3
βx = 1.75 / (λx + 1.0) = 1.75/(0.300+1.0) = 1.346
βhs * βx * ft * byo * ho = 1.00*1.346*1.43*2500*790 = 3809561N
≥ Vy = 2927070N,满足要求。
4、柱下局部受压承载力计算:
局部荷载设计值 F = 5854140N
混凝土局部受压面积 Al = bc * hc = 490000mm
承台在柱下局部受压时的计算底面积按下列公式计算:
Ab = (bx + 2 * c) * (by + 2 * c)
c = Min{Cx, Cy, bx, by} = Min{900,900,700,700} = 700mm
Ab = (700+2*700)*(700+2*700) = 4410000mm
βl = Sqr(Ab / Al) = Sqr(4410000/490000) = 3.000
ω * βl * fcc * Al = 1.0*3.000*0.85*14.33*490000 = 17907120N
≥ F = 5854140N,满足要求。
5、桩局部受压承载力计算:
局部荷载设计值 F = Nmax + γg * Qgk = 1463.5+1.35*66.8 = 1553.8kN
混凝土局部受压面积 Al = π * d ^ 2 / 4 = 196350mm
承台在角桩局部受压时的计算底面积按下列公式计算:
Ab = (bx + 2 * c) * (by + 2 * c)
圆桩 bx = by = Sqr(Al) = 443mm
c = Min{Cx, Cy, bx, by} = Min{250,250,443,443} = 250mm
Ab = (443+2*250)*(443+2*250) = 889463mm
βl = Sqr(Ab / Al) = Sqr(889463/196350) = 2.128
ω * βl * fcc * Al = 1.0*2.128*0.85*14.33*196350 = 5090815N
≥ F = 1553764N,满足要求。 五层教学楼框剪结构建筑设计和结构设计计算书和CAD图纸(74):http://www.youerw.com/gongcheng/lunwen_1083.html