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5吨装载机前车架焊接变位机回转传动机构设计+CAD图纸+答辩PPT(10)

时间:2017-02-06 08:55来源:毕业论文
(2)已知载荷条件,选取机型和规格 已知工作转矩 =5600N.m和工作转速 =0.65r/min 基本功率 = (4.1) = =0.4kW 配用电机功率 N= K (4.2) =0.41.2 =0.48kW 额定功率 [N]N (4


(2)已知载荷条件,选取机型和规格
已知工作转矩 =5600N.m和工作转速 =0.65r/min
基本功率                  =                              (4.1)
                             =
                             =0.4kW     
配用电机功率                 N= ×K                               (4.2)
                              =0.4×1.2
                              =0.48kW
额定功率                    [N]>N                                   (4.3)
                            2.2>0.48符合条件
已知工作转矩 =3000N.m和工作转速 =0.8r/min
基本功率                  =                               (4.4)
                            =
                            =0.26kW     
配用电机功率               N= ×K                                (4.5)
                            =0.26×1.2
                            =0.312kW
额定功率                  [N]>N                                     (4.3)
                         0.75>0.312符合条件
根据传动比 =11在表4.3中选择减速机型号

  5吨装载机前车架焊接变位机回转传动机构设计+CAD图纸+答辩PPT(10):http://www.youerw.com/jixie/lunwen_2544.html
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